x+(x^2-2x+1)=3

Solution for x+(x^2-2x+1)=3 equation:

Simplifying
x + (x2 + -2x + 1) = 3

Reorder the terms:
x + (1 + -2x + x2) = 3

Remove parenthesis around (1 + -2x + x2)
x + 1 + -2x + x2 = 3

Reorder the terms:
1 + x + -2x + x2 = 3

Combine like terms: x + -2x = -1x
1 + -1x + x2 = 3

Solving
1 + -1x + x2 = 3

Solving for variable 'x'.

Reorder the terms:
1 + -3 + -1x + x2 = 3 + -3

Combine like terms: 1 + -3 = -2
-2 + -1x + x2 = 3 + -3

Combine like terms: 3 + -3 = 0
-2 + -1x + x2 = 0

Factor a trinomial.
(-1 + -1x)(2 + -1x) = 0

Subproblem 1
Set the factor '(-1 + -1x)' equal to zero and attempt to solve:

Simplifying
-1 + -1x = 0

Solving
-1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1x = 0 + 1
-1x = 0 + 1

Combine like terms: 0 + 1 = 1
-1x = 1

Divide each side by '-1'.
x = -1

Simplifying
x = -1
Subproblem 2
Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying
2 + -1x = 0

Solving
2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 0 + -2
-1x = 0 + -2

Combine like terms: 0 + -2 = -2
-1x = -2

Divide each side by '-1'.
x = 2

Simplifying
x = 2
Solution
x = {-1, 2}